Identify the vertex and axis of symmetry of the function f(x) = -(x + 1)^2 + 2 *
x = -1; (-1, 2)
x = 1; (1, 2)
x = -2; (2, -1)
x = 2; (2, 1)

x = -1; (-1, 2)

Step-by-step explanation:

f(x) = -(x + 1)^2 + 2

This is in vertex form

y = a(x-h)^2 +k  where the vertex is (h,k) and the axis of symmetry is x=h

f(x) = -(x -  -1)^2 + 2

Axis of symmetry is x=-1

Vertex is (-1,2)

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation:

hi there!

the answer will be d: 2