What is the midpoint of EC ?

A: (t + p, r)

B: (p – t, r)

C: (2p – 2t, r)

D: (p, r)

Given:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

Midpoint of EC:

The midpoint of EC can be determined using the formula,

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Simplifying, we get;

Dividing, we get;

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.