Where on a number line are the numbers x for which

|x|>1

Step-by-step explanation:

Given the inequality

|x|> 1

The modulus of x shows that x can be both positive and negative value.

If x is positive:

x>1

1<x

If x is negative:

-x>1

Multiplying both sides of the inequality by minus will change the inequality sign

x < -1

Combining both inequalities:

1<x<-1

Find the position on the number line in the attachment

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5