Using the digits 1 to 9 at most one time each place a digit in each box to create an equation where X is a negative value serve you equation to prove your answer

The solution set of equations assuming x as a negative value can go from:

x + 9 = 2, that gives us the least possible negative value of - 7 to:

x + 3 = 2, that gives us the highest negative value of - 1 to x

The only condition is that the second term of the equation should be a higher number than the result.

Step-by-step explanation:

If x is a negative value, let's create the set of equations using digits from 1 to 9 one time, this way:

a. x + 9 = 2

x = 2 - 9

x = -7

b. x + 9 = 3

x = 3 - 9

x = - 6

c. x + 3 = 2

x = 2 - 3

x = -1

d. x + 4 = 2

x = 2 - 4

x = -2

e. x + 6 = 5

x = 5 - 6

x = -1

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180