A 12 sided die with sides labeled 1 through 12 will be rolled once each number greater than 10?

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Step-by-step explanation:

Total No. of rolling each side of the 12-sided die= 12 x 12= 144 outcomes

No. of outcomes equals 10 are: (1, 9), (9, 1), (2, 8), (8, 2), (3, 7), (7, 3), (4, 6), (6, 4), (5, 5) = 9 outcomes.

No. of outcomes of rolling a No. >10: 144–9 = 135 outcomes.

Probability, Pr, of rolling a No. >10= 135/144

Pr (No. >10) = 0.9375 (to 4 dec. pl.)

I think you’re missing something on your question. But I think what your asking is how many numbers greater than 10. It should 2/12 or

Step-by-step explanation:

$450 is the answer.

step-by-step explanation:

30% of 450 = 135

450-135=315