The area of a rectangular fountain is x2 + 9x + 20 square feet. A 3-foot walkway is built around the fountain. Find the dimensions of the outside border of the walkway. The dimensions of the outside border of the walkway are

(x+11) by (x+10)

Step-by-step explanation:

We know that Area = Length x width

Given: Area = x²+9x+20

Lets sort this out first

Area = x²+5x + 4x + 20

Area = x(x+5) + 4(x+5)

Area = (x+5) (x+4)

Therefore, it is concluded that:

Length 'l' = (x+5) feet

Width 'w' = (x+4) feet

if a 3-foot walkway is built around the fountain, we'll add 3 feet on both sides

Therefore,

Outer Length = (x+5+3+3) = (x+11) feet

Outer Width = (x+4+3+3) = (x+10) feet

The fountain is (x+5) by (x+4).  

dimensions of the outside border of the walkway are (x+11) by (x+10)

just needed some points but try socratic

step-by-step explanation:

in which figure is point g a centroid