Mathematics, 23.04.2020 01:16 hellomlatasha7134

A sports shop sold 5000 baseball cards this year in a four month period from the 1st of April until the end of July. 30% of the cards were sold in the month of May. There were 300 more cards sold during June than in July and 400 less cards were sold during April compared to July. What percentage of cards were sold in April?

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Answer from: xojade

16%

Step-by-step explanation:

GIVEN: A sports shop sold 5000 baseball cards this year in a four month period from the 1st of April until the end of July. $30\%$ of the cards were sold in the month of May. There were 300 more cards sold during June than in July and 400 less cards were sold during April compared to July.

TO FIND: What percentage of cards were sold in April What percentage of cards were sold in April.

SOLUTION:

Total cards sold =5000

Let total cards sold in July be

According to question

Cards sold in June =300+x

Cards sold in April =x-400

Total cards sold in may $=30\%\ of\ 5000=\frac{30}{100}\times5000$

=1500

Total cards sold =x+300+x+x-400+1500=5000

$\therefore 3x=3600\implies x=1200$

cards sold in April $=x-400=1200-400\implies x=800$

percentage of cards sold in April $=\frac{\text{cards sold in April}}{\text{total cards}}\times100$

$=\frac{800}{5000}\times100=16\%$

Hence 16% of total cards were sold in April

Answer from: Quest

r and t.

both are 64 degrees.

17. given triangle rst as shown below. which two sides of the triangle are congruent to each other?

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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