1. Use the slopes (5, 7) and (-4, -2) from the previous question to describe each line as slanting downward, slanting upward, horizontal, or vertical. Explain your answers.

2. Find the slopes of lines AB and CD. Show your work.
A: Line AB goes through points A(3, 4) and B(7, 7).
B: Line CD goes through points C(0, 0) and D(-6, 8).

3. A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.
Write an equation for line p.
Part I: Find the slope of AB. Show your work.
Part II: Use the slope from Part I and point C to write an equation for line p in slope-intercept form. Show your work.

1. slanting upward because the slope is positive one.

2. A: 3/4     B: 4/-3

3. A: 3        B: y=3x-10

Step-by-step explanation:

1. (-2-7)/(-4-5) = -9/-9 = 1

2. A: (7-4)/(7-3) = 3/4

   B: (8-0)/(-6-0) = 8/-6 = 4/-3

3. find the slope first so (4-1)/(2-1)= 3/1. then you plug in point C to find the y intercept so y=mx+b would be 2=3(4)+b which makes it so b is -10. the new equation would be y=3x-10

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet