A scuba diver descended 13 5/12 feet below sea level. Then , he descended another 3 3/5 feet. What is the location of the diver after his second descent?

The final depth of the diver is 19.1 feet or 19 1/10 feet.

Step-by-step explanation:

In order to solve this problem we first need to convert the mixed fractions to decimals, to make the math easyer. To do that we sum the integer part with the fraction part as shown bellow:

distance 1 = 13 + 5/2 = 13 + 2.5 = 15.5 feet

distance 2 = 3 + 3/5 = 3 + 0.6 = 3.6 feet

Since the diver descended two times the final depth after his second descent is the sum of both distances. We have:

final depth = 15.5 + 3.6 = 19.1 feet = 19 1/10 feet

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752