A farmer has some buffalos and peacocks. One day he observed that his animals witch are normal, have 78 eyes and 110 legs. How many animals of each type does he have ?

there were 16 buffalos and 23 peacocks.

Step-by-step explanation:

Let x represent the number of Buffaloes.

Let y represent the number of peacocks.

A Buffalo has 2 eyes while a peacock has 2 eyes. If the Buffalo and the peacock has 78 eyes in total, then

2x + 2y = 78

Dividing both sides of the equation by 2, it becomes

x + y = 39

x = 39 - y

A Buffalo has 4 legs while a peacock has 2 legs. If the Buffalo and the peacock has 110 in total, then

4x + 2y = 110- - - - - - - - - - - - 1

Substituting x = 39 - y into equation 1, it becomes

4(39 - y) + 2y = 110

156 - 4y + 2y = 110

- 4y + 2y = 110 - 156

- 2y = - 46

y = - 46/- 2

y = 23

x = 39 - y = 39 - 23

x = 16

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

step-by-step explanation:

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