A buyer for a grocery chain inspects large truckloads of apples to determine the proportion p of apples in the shipment that are rotten. she will only accept the shipment if there is clear evidence that this proportion is less than 0.06 she selects a simple random sample of 200 apples from the over 20000 apples on the truck to test the hypotheses h0: p = 0.06, ha: p < 0.06. the sample contains 9 rotten apples. the p-value of her test is

The p-value of her test is 0.15386.

Step-by-step explanation:

We are given that a buyer for a grocery chain inspects large truckloads of apples to determine the proportion p of apples in the shipment that are rotten.

She selects a simple random sample of 200 apples from the over 20000 apples on the truck and the sample contains 9 rotten apples.

Let p = proportion of of apples in the shipment that are rotten.

SO, Null Hypothesis, : p = 0.06   {means that the proportion of apples in the shipment that are rotten is equal to 0.06}

Alternate Hypothesis, : p < 0.06   {means that the proportion of apples in the shipment that are rotten is less than 0.06}

The test statistics that will be used here is One-sample z proportion statistics;

                               T.S.  =  ~ N(0,1)

where, = proportion of apples that are rotten in a sample of 200 apples =  = 0.045  

           n = sample of apples = 200

So, test statistics  =  

                              =  -1.02

The value of the test statistics is -1.02.

Now, P-value of the test statistics is given by;

        P-value = P(Z < -1.02) = 1 - P(Z 1.02)

                                            = 1 - 0.84614 = 0.15386

Hence, the p-value of her test is 0.15386.

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).