How would you describe the relationship between the real zero(s) and x-intercept(s) of the function flx) =-
intercanta of the function du
37(4-1)
%2C+3)(4+1)
When you set the function equal to zero, the solution is x = 1, therefore, the graph has an x-intercept of (1,0)
When you set the function equal to zero, the solutions are x = 0 or x = 1 therefore, the graph has x-intercepts at (0,0) and
(1,0)
When you substitute x = 0 into the function, there is no solution, therefore, the graph will not have any x-intercepts.
Since there are asymptotes at x = -3, 3-1, and x = 0, the graph has no x-intercepts and, therefore, no real zeros.