In ΔCDE, the measure of ∠E=90°, the measure of ∠D=38°, and DE = 12 feet. Find the length of CD to the nearest tenth of a foot.

Given:

Given that the triangle CDE is a right triangle.

The measure of ∠E is 90° and ∠D is 38°

The length of DE is 12 feet.

We need to determine the length of CD.

Length of CD:

The length of CD can be determined using the trigonometric ratio.

Thus, we have;

where and the side adjacent to angle D is ED and hypotenuse is CD.

Substituting these values, we get;

where ∠D = 38°, ED = 12 feet.

Substituting, we get;

Simplifying, we have;

Dividing, we get;

Thus, the length of CD is 15.2 feet.

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