Solve the inequality t/4 >7
And 2c/3 +1>7

  c > 12

Step-by-step explanation:tep  1  :

           c

Simplify   —

           3

Equation at the end of step  1  :

       c            

 ((2 • —) -  1) -  7  > 0  

       3            

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        1     1 • 3

   1 =  —  =  —————

        1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2c - (3)     2c - 3

————————  =  ——————

   3           3    

Equation at the end of step  2  :

 (2c - 3)    

 ———————— -  7  > 0  

    3        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        7     7 • 3

   7 =  —  =  —————

        1       3  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(2c-3) - (7 • 3)     2c - 24

————————————————  =  ———————

       3                3    

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  2c - 24  =   2 • (c - 12)  

Equation at the end of step  4  :

 2 • (c - 12)

 ————————————  > 0  

      3      

Step  5  :

5.1    Multiply both sides by  3  

5.2    Divide both sides by  2  

Solve Basic Inequality :

5.3      Add  12  to both sides

            c > 12

Inequality Plot :

5.4      Inequality plot for

        0.667 X  - 8.000  >  0

One solution was found :

                  c > 12

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.