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Mathematics, 23.04.2020 15:45 1lowz1k

Cos^2x*sin^4x= A+Bcos2x+C cos4x+D cos2xcos4x
Find A, B,C, and D

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Cos^2x*sin^4x= A+Bcos2x+C cos4x+D cos2xcos4x
Find A, B,C, and D...
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