Mathematics, 23.04.2020 15:51 lalllda

Suppose you have a bag with 50 letter tiles in it and 11 of the tiles are the letter Upper C. If you pick a letter tile at random from the bag, the probability that it is the letter Upper C is StartFraction 11 Over 50 EndFraction . Suppose another bag has 300 letter tiles in it and 168 of the tiles are the letter Upper C. Write the probability of picking a tile that is the letter Upper C as a fraction and as a percent. From which bag are you more likely to pick a tile that is the letter Upper C?

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Answer from: Quest

mr. flanders’ class sold 47 doughnuts and mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

$\left\{\begin{array}{l}x+y=85\\1.35x+1.08y=104.49\end{array}\right.\rightarrow \left\{\begin{array}{l}x=85-y\\1.35(85-y)+1.08y=104.49\end{array}\right.$

$114.75-1.35y+1.08y=104.49,\\ \\114.75-104.49=1.35y-1.08y,\\ \\10.26=0.27y,\\ \\y=38,\\ \\x=85-38=47.$

Answer from: Quest

168

step-by-step explanation:

i am pretty sure that the answer is 168

Answer from: Quest

see attached

step-by-step explanation:

given the function as;

$f(x)=2x^3-7x^2+2x+3$

write the equation replacing f(x) with y

$y=2x^3-7x^2+2x+3$

form and fill a table containing values of y with corresponding values of x

you can take a range for values of x as -3≤x≤3

solving for x=-3

$f(-3)=2*-3^3-7*-3^2+2*-3+3=2*-27-63+-6+3=-54-63-6+3y=-120$

for x=-2

$f(-2)=2*-2^3-7*-2^2+2*-2+3=2*-8-28+-4+3=-16-28-4+3=-45$

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values of x and obtain the following graph

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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