A triangle has vertices at B(-3,0), C(2.-1). D(-1, 2). Which transforffiation would produce an image with vertices B*(1, -2), C"(0,3). D"(3, 0)?

(x, y) - (x + 1, y + 1). (X, y) - (y, x)

(x, y) - (x + 1, y + 1), (x, y) - (-x, y).

(x, y) - (X. -y). (X. y) - (x + 2 y + 2)

(x, y) - (-x, y). (x, y) - (x + 2, Y + 2)

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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answer:   rotate 270° clockwise about (7, 1) and reflect across the line x = 7

step-by-step explanation:

because i took test

i don't see any

step-by-step explanation: