Write an equation in vertex form of the parabola that passes through (4, 20) and has a vertex of (1, 2). *

f(x) = 2(x - 1)² + 2

Step-by-step explanation:

The vertex form is f(x) = a(x - h)² + k, where the vertex is (h, k).

Putting in the given vertex, we get  f(x) = a(x - 1)² + 2. To find a, we put in the other point that the parabola passes through (4, 20) which is [x, f(x)].

20 = a(4 - 1)² + 2

20 = a(3)²  +  2

20 = 9a + 2    (subtract 2 from both sides to get a alone)

-2            -2

18  =  9a    (divide both sides by 9 to get a by itself)

9       9

2 = a   (put that into our vertex form equation)

f(x) = 2(x - 1)² + 2

answer: just subtact the units and then add the non negative : happy to

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~