A line passes through the points (1. 4) and (3.-4). Which is the equation of the line?
O
y=-4x+8
y=-2x + 8
0 - - 4x + 2
o y= 2x+2

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope(m), use the slope formula:

      And plug in the two points on the line

(1, 4) = (x₁, y₁)

(3, -4) = (x₂, y₂)

   Simplify the fraction

m = -4  

Now that you know the slope, substitute/plug it into the equation.

y = mx + b

y = -4x + b   To find b, plug in either of the points into the equation, it doesn't matter which, the isolate/get the variable "b" by itself. I will use (1, 4)

4 = -4(1) + b     Add 4 on both sides to get "b" by itself

4 + 4 = -4 + 4 + b

8 = b

y = -4x + 8     Your answer is the 1st option

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )