Find the 6th term of the following geometric sequence:
2, 8, 32, 128, ...

Step-by-step explanation:

t1 = 2= 2 * 4 ^ 1 -1

t2 = 8= 2* 4^2-1

t3 = 32= 2 * 4^3 -1

t4 = 128 = 2* 4^ 4 -1

tn = 2 * 4^ (n - 1)

Now

the 6th term of the sequence is

t6 = 2 * 4^ 6 -1

    = 2 * 1024

    = 2048

hope it was helpful.

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

need more info

step-by-step explanation: