Calculate the vertex of the parabola using the equation
Please helppp meee :((

FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)

10. y = (x+2)^2 - 11 --> (-2, -11)

11. y = -(x-4)^2 + 32 --> (4, 32)

12. y = 3(x-1)^2 - 5 --> (1, -5)

13. y = -2(x+2)^2 + 5 --> (-2, 5)

14. y = 2(x+1)^2 - 1 --> (-1, -1)

15. y = -5(x-1)^2 + 8 --> (1, 8)

16. y = 3(x-3)^2 - 26 --> (3, -26)

17. y = (x+5)^2 - 32 --> (-5, -32)

18. y = -(x-3)^2 + 10 --> (3, -10)

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3