The balanced scale represents the equation: 3x + 1 = x + 3

If one x block is subtracted from the right side and three numbered blocks are subtracted from the left side. What process will balance the scale?
A) subtract one x block from the left side and subtract three numbered blocks from the left side
B) subtract one x block from the left side and subtract three numbered blocks from the right side
C) subtract one x block from the right side and subtract three numbered blocks from the left side
D) subtract one x block from the right side and subtract three numbered blocks from the right side

Given:

The given balanced scale is represented by the equation

----- (1)

We need to determine the process that balance the scale.

Process to balance the scale:

Given that the if one x block is subtracted from the right side and three numbered blocks are subtracted from the left side.

Thus, the equation (1) becomes

        ----- (2)

Now, to balance the scale, let us subtract one block x from the left side and subtract three numbered blocks from the right side.

Thus, the equation (2) becomes,

        ------ (3)

Thus, the equation (3) is the same as the equation (1).

Hence, the process required to balance the scale is to subtract one x block from the left side and subtract three numbered blocks from the right side.

Therefore, Option B is the correct answer.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

simplifying:

to further simplify this radical, we need to use the property  

thus