A picture measuring 2 inches by 3 inches is placed inside a frame. The width between the picture and the frame is equal around the entire picture. If the area of the frame and the picture is 72 square inches, what is the width of the frame? Please explain!

  hope this helped

Step-by-step explanation:

   This is where it gets a little tricky. For example, 11x14 frames (which refers to the inside perimeter of the frame) used to frame an 8x10 image could be referred to as both an 8x10 frame or an 11x14 frame, assuming the complete frame package contains the appropriate mat board. However, an 11×14 frame with no mat will always be an 11×14 frame.

So is the frame dimension 11×14 or 8×10? The answer is neither.

If the frame size—not the mat opening—says 11×14, it is referring to the inside dimension. However, the frame will be cut slightly larger (typically 1/8 inch). This extra space allows room for the glazing, mounting board and mat board to fit without binding. It also allows for up to 1/16 inch error on the mat and glazing dimension as well as for expansion and contraction due to temperature changes.

When you’re purchasing a frame from Frame Destination, be it one of our largest or smallest like our 5x7, the size frame you select depends on whether or not you are including mat board. If you are including mat board, the frame size will be larger than the artwork size. If you are not including mat board, the frame size will match the artwork.

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.