A locker combination has three nonzero digits and digits cannot be replaced. The first two digits are 9 and 8. What is the probability that the third digit is 7?

1 in 7

Step-by-step explanation:

Your one-digit choices: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they're nonzero, so: 1, 2, 3, 4, 5, 6, 7, 8, 9.

But they can't be repeated and 9 and 8 are used, so: 1, 2, 3, 4, 5, 6, 7.

Only 7 numbers left, so chances are, 1 in 7.

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

1.0

step-by-step explanation: