Mathematics, 24.04.2020 21:51 sierrastrickland99
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected from a sample of 81 business students over a one-week period. Assume the population standard deviation is 1.2 hours. If the sample mean is 9 hours, then the 95% confidence interval is approximately . a. 7.80 to 10.20 hours b. 8.74 to 9.26 hours c. 7.36 to 10.64 hours d. 7.04 to 110.96 hours
Answers: 3
Mathematics, 22.06.2019 01:40
Given: prst square pmkd is a square pr = a, pd = a find the area of pmct.
Answers: 3
Mathematics, 22.06.2019 02:30
According to a research study, parents with young children slept 6.4 hours each night last year, on average. a random sample of 18 parents with young children was surveyed and the mean amount of time per night each parent slept was 6.8. this data has a sample standard deviation of 0.9. (assume that the scores are normally distributed.) researchers conduct a one-mean hypothesis at the 5% significance level, to test if the mean amount of time parents with young children sleep per night is greater than the mean amount of time last year. the null and alternative hypotheses are h0: ฮผ=6.4 and ha: ฮผ> 6.4, which is a right-tailed test. the test statistic is determined to be t0=1.89 using the partial t-table below, determine the critical value(s). if there is only one critical value, leave the second answer box blank.
Answers: 3
In order to estimate the average time spent on the computer terminals per student at a local univers...
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