According to a survey, 58% of people carry at least 1 reusable water bottle. If 5 people are selected randomly, what is the probability that at least 4 of them will be carrying a reusable water bottle? Round your answer to the nearest tenth of a percent.

The probability that at least 4 of them will be carrying a reusable water bottle is 30.3%.

Step-by-step explanation:

Here it is given that probability of people who carry at least 1 reusable water bottle is p = 0.58.

A random sample of n = 5 people are selected.

This data follows binomial distribution, with success denoted by a a person carrying t least 1 reusable water bottle. The probability mass function of binomial distribution is,

Compute the probability that at least 4 of them will be carrying a reusable water bottle as follows:

P (X ≥ 4) = P (X = 4) + P (X = 5)

The percentage is, 0.3033 × 100 = 30.3%.

Thus, the probability that at least 4 of them will be carrying a reusable water bottle is 30.3%.

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

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