A soccer field is bordered on three sides by a parking lot of a width x. the total length of the field and parking lot is 300 M and a total width is 200 M the area of the field is 30000 M squared how wide is the parking lot

Parking lot is 60m wide

Step-by-step explanation:

Since the parking lot is x meters, the length of the field would simply be (300-2x)m while the width of the field would be (200-x). The width would also have been 200-2x but we must remember that the field is only covered on 3 sides.

Area of the field is 30,000. This means if we multiply both, we get 30,000.

Mathematically;

(300-2x)(200-x) = 30,000

60,000-300x-400x+ 2x^2 = 30,000

2x^2-700x-30,000= 0

We can see we now have a quadratic equation we need to solve.

2x^2+500x-1200x-30,000= 0

2x(x+250) -120(x+250) = 0

(2x-120)(x+250) = 0

2x-120= 0 or x+250=0

2x = 120or x = -250

x = 120/2 or x= -250

x = 60 or x=-250

We discard x = -100 as x is length and cannot be negative

Hence, x = 60m

555.99.

step-by-step explanation:

hope this

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0