The graph shows the motion of two cars starting at different places on a highway. Their speeds can be compared by comparing the steepness of the graphed lines.

Use the drop-down menus to complete the statements.
Car a travels (50,100,200,300) miles in 6 hours Car B travels (50,100,200,300) miles in 5 hours
Car A speed is (40,50,60,125,) miles per hour Car B speed is(40,50,60,125) miles per hour.
Car A traveled (faster than, slower than, the same speed) as Car B.
The graph for Car A is(steeper than, less steeperhan, or same steepness) as the graph for Car B

Car a travels (300) miles in 6 hours

Car B travels (200) miles in 5 hours

Car A speed is (50) miles per hour

Car B speed is(40) miles per hour.

Car A traveled (faster than) Car B.

The graph for Car A is(steeper than) the graph for Car B

Step-by-step explanation:

where x is starting location and y is the ending location

the rest we see once we have solve for distance and speed of the 2 cars

its on ttm

Step-by-step explanation:

got it right

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9