If a ball is thrown upward at 29.4 meters per second from the top of a building that is 80 meters high, the height of the ball can be modeled by S=4.9t^2 + 29.4t + 80 meters, where t is the number of seconds after the ball is thrown. What is the ball's maximum height (in meters)?

Step-by-step explanation:

29.4 per sec > Building 80m

Height = S = 4.9t^2 + 29.4t + 80

Solve for t:

t = 1.24 (approximately)

If t needed coordinates / solve using the quadratic formula:

t = (1.24 , -7.24)

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: