An object is taken from a freezer at negative 7 degrees Upper C. Let t be the time in hours after the object was taken from the freezer. At time t the average temperature of the object is increasing at the rate of Upper T prime (t )equals 10 e Superscript negative 0.5 t degrees Celsius per hour. Find the temperature of the object at time t.

Step-by-step explanation:

The object is taken from a freezer at

To determine the temperature T(t), at any time t, we take the integral of the average increase in temperature.

The temperature of the object at time t is given as:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

a

step-by-step explanation:

the answer is a