What is the volume of a cone with a radius of 3 feet and a slant height of 6 feet? Use full value for pi. Round your answer to the nearest hundredth. (4 points)

The volume of this cone is 48.91 cubic feet.

Step-by-step explanation:

In order to calculate the volume of this cone we need to use the appropriate formula as shown bellow:

Volume = (1/3)*pi*r²*h

But we have the slant height of the cone and not the height needed, in order to calculate that that we must use Pytagora's theorem, where the slant height is the hypothenuse, the radius of the base is one of the cathetus and the height of the cone is the other so we have:

6² = 3² + h²

h² = 36 -9 = 27

h = sqrt(27) = 3*sqrt(3)

So the volume is:

Volume = (1/3)*pi*(3)²*3*sqrt(3) = pi*9*sqrt(3) = 9*1.73*pi

Volume = 15.57*3.14159 = 48.91 cubic feet.

The volume of this cone is 48.91 cubic feet.

  21.3

step-by-step explanation:

multiplying the given equation by c/sin(25°), we get

  c = 9/sin(25°) ≈ 21.2958 ≈ 21.3

we assume "c" is the length of ab, the side opposite angle c in triangle abc.

step-by-step explanation:

bob the banana