In the equation (x+2)^2+(y-3)^2=4, the radius of the circle is

From the equation of a circle, we want to get the radius of the same circle.

We will see that the radius is equal to 2.

First, let's describe the general equation of a circle.

For a circle of radius R centered in the point (h, k) the equation is:

(x - h)^2 + (y - k)^2 = R^2

Here, we got the equation:

(x+2)^2 + (y-3)^2 = 4

We can rewrite it to:

(x- (-2))^2 + (y-3)^2 = 2^2

Then we can see that this is a circle of radius equal to 2 centered at (-2, 3), the graph of the circle can be seen below.

Concluding the radius of the circle is equal to 2.

If you want to learn more, you can read

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center = (-2, 3)

radius = 2

Step-by-step explanation:

(x+2)^2   +  (y-3)^2 =  4

Use the formula:   (x - h)^2   +  (y - k)^2  = r^2

where (h, k) = center,   radius = r

mysticchacha dot com

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(x - (-2))^2   +  (y - 3)^2 =  4 =  (2)^2

center = (-2, 3)

radius = 2

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.