) Explain why the sample midrange might be preferred to the sample mean as an estimator of the population mean.

In this exercise we have to analyze the graph informing and calculate the midrange, that is, the average between the highest and lowest value, so:

It is a good Estimator of the Population Mean because the distribution of the sample midrange is just same as the distribution of the random variable. So we can say the midrange value is .  

In this exercise, we have to analyze the graph informed in the question and from it observe what is requested, then:

The sample midrange can be computed as:

The sample midrange uses only a small portion of the data, but can be heavily affected by outliers. It provides information about the skewness and heavy-tailedness of the distribution which is just same as the distribution of the random variable. The nature of this distribution is not intuitive but the Central Limit in which it will approach a normal distribution for large sample size.

See more about midrange at link

It is a good Estimator of the Population Mean because the distribution of the sample midrange is just same as the distribution of the random variable.

Step-by-step explanation: from the table,

Minimum value = 34

maximum values = 1084

The sample mid-range can be computed as:

(Min.value + max.value)/2

(34 + 1084)/2

Sample mid-range = 55

The sample midrange uses only a small portion of the data, but can be heavily affected by outliers.

It provides information about the skewness and heavy-tailedness of the distribution which is just same as the distribution of the random variable.

The nature of this distribution is not intuitive but the Central Limit in which it will approach a normal distribution for large sample size.

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

i think it would be c

mark brainliest if im right

step-by-step explanation: