Use the quadratic formula to solve x^2-5x-2=0

we know

X = -b±(√b^2-4ac)

2a

NOW COMPARING X^2-5X-2=0 WITH AX^2+BX+C=0

WE GET

A=1

B=-5

C=-2

AGAIN,

X=-(-5)±√(-5)^2-4×1×(-2)

2×1

TAKING POSITIVE and negative you can find out answer

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

b. hoped i'm right lol

step-by-step explanation: