What is the lcd of (3x)/(x + 3), 3/(x ^ 2 - 9)

Simplify the denominator.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

x

2

−

5

x

+

6

Factor

x

2

−

5

x

+

6

using the AC method.

Tap for more steps...

x

(

x

+

3

)

(

x

−

3

)

⋅

3

x

(

x

−

3

)

(

x

−

2

)

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

(

x

+

3

)

(

x

−

3

)

,

(

x

−

3

)

(

x

−

2

)

The LCM is the smallest positive number that all of the numbers divide into evenly.

1. List the prime factors of each number.

2. Multiply each factor the greatest number of times it occurs in either number.

The number

1

is not a prime number because it only has one positive factor, which is itself.

Not prime

The LCM of

1

,

1

is the result of multiplying all prime factors the greatest number of times they occur in either number.

1

The factor for

x

+

3

is

x

+

3

itself.

(

x

+

3

)

=

x

+

3

(

x

+

3

)

occurs

1

time.

The factor for

x

−

3

is

x

−

3

itself.

(

x

−

3

)

=

x

−

3

(

x

−

3

)

occurs

1

time.

The factor for

x

−

2

is

x

−

2

itself.

(

x

−

2

)

=

x

−

2

(

x

−

2

)

occurs

1

time.

The LCM of

x

+

3

,

x

−

3

,

x

−

3

,

x

−

2

is the result of multiplying all factors the greatest number of times they occur in either term.

(

x

+

3

)

(

x

−

3

)

(

x

−

2

)

Step-by-step explanation:

there does that help

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v