The vertex form of a quadratic function is flax) = a (x - h)2 + k. What is the vertex of each function? Match the function
rule with the coordinates of its vertex.
f(x) = 9(x - 5)2 + 6
(6.9)
f(x) = 5(x - 6)2 + 9
(5.-9)
f(x) = 6(x + 9)2 -5
(5.6)
f(x) = 9(x + 5)2 - 6
(-9.-5)
f(x) = 6(x - 5)2 - 9
(-5, -6)

Our functions are

1. 9(x - 5)^2 + 6

2. 5(x - 6)^2 + 9

3. 6(x + 9)^2 - 5

4. 9(x + 5)^2 - 6

5. 6(x - 5)^2 - 9

To get the vertex, referring to a(x - h)^2 + k, we only need h and k. The vertex will be at (h, k), so using this, we can go back and find h and k.

1. (5, 6)

2. (6, 9)

3. (-9, -5)

4. (-5, -6)

5. (5, -9)

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5