The first term of a geometric progression is 3 and the common ratio is 2 a)Write down the forth term of the progression b)write down the sixth term of the progression

a) Fourth term of the progression is 24

b) Sixth term of the progression is 96

Step-by-step explanation:

Formula for geometric sequence is,

where

a = first term of sequence

r = common ratio

Given that first term of GP is 3. So, a = 3. Also common ratio is 2. So, r = 2.

a) To find fourth term of progression that is, .

Substituting the values in given formula,

Simplifying,

Therefore, the fourth term of progression is 24

b) To find sixth term of progression that is, .

Substituting the values in given formula,

Simplifying,

Therefore, the sixth term of progression is 96

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.