What is 3-+3(4)4+3

Yo mia

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Step-by-step explanation:

First I have 1/3 to the ninth power times 1/3 to the negative fifth power. Notice that the base in both powers is 1/3. I'm going to keep my base the same, 1/3, and I'm going to add my exponents. So now I have 9 plus negative 5. Adding 9 and negative 5 gives me 1/3 to the fourth power. This can also be written as 1/81.Let's take a look at another example. Negative 7 to the third times negative 7 to the 0 times negative 7 to the negative 2. All of these powers have a base of negative 7. So I just need to add the exponents. And it's going to give me negative 7 to the 3 plus 0 plus negative 2. Adding those exponents leaves me with negative 7 to thefirst power, which is just negative 7. Let's take a look at a few common misconceptions with this. First, consider the product of powers of the same base, 4 to the second times 4 to the fifth. If we add the exponents, we get 4 to the power of 2 plus 5, which is 4 to the seventh power. If we multiply the exponents, we get 4 to the power of 2  times 5, which is 4 to the 10th. So which one is correct? Let's take a look at the original problem. 4 to the second times 4 to the fifth. If I write this out as factors of 4, I have two factors of 4. 4 times 4, times 5 factors of 4. So 4 times 4 times 4 times 4 times 4. How many total factors of 4 do we have?

We have 1, 2, 3, 4, 5, 6, 7. So it's obvious that adding the exponents is the correct answer, because 4 to the seventh is seven factors of 4. One other note I want to make is that we don't multiply the base. Notice that the base stays the same. So 4 to the second times 4 to the fifth is not 16 to the seventh.

This would be seven factors of 16, which is not the same as seven factors of 4.

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step-by-step explanation:

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5