PLS HELP: How do you solve x^2-ax-6a^2=0 by completing the square?

x = a/2 + 6.5 a^2

Step-by-step explanation:

x^2-ax-6a^2=0

Assuming a is a constant, let's move the third term to the right:

x^2-ax=6a^2

Now we need to add something to both sides to make it a perfect square.

x^2-ax + = 6a^2 +

We need to add a/2 ^2 to both sides. (This is a standard part of completing the square, wherein you add b/2 ^2. Like if you had 8x as your middle term, you add 16.)

x^2-ax + a/2 ^2 = 6a^2 + a/2 ^2

Factor the left side, because it's a perfect square now:

(x - a/2)(x - a/2) = 6.5 a^2

(x - a/2)^2 = 6.5 a^2

Take the square root of both sides:

x - a/2 = 6.5 a^2

x = a/2 + 6.5 a^2

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

step-by-step explanation: