From A, a point due west of a tower QT of height h meters, the angle of elevation of the top of the tower is 60 degrees. From point B, a point 200 meters due south of A, the angle of elevation of the stop of the tower is 30 degrees. The point A, B and T are on the same ground level.

(a) Show that AT = h/sqrrt 3
(b) Show that h = 50 x sqrrt 6

(C) calculate the bearing (to the nearest degree) of B from the base of the tower.

The answer should be c.

One shot. if 60% of 10 is 6, then what is 70%? we know it would be seven (since 60% is mathematically 60/100, or 6/10, then 70% is 70/100, or 7/10) but we can check anyway using ratios: 6 : 60% = x : 70%*inverse multiplicationx * 60% = 6 * 70%*divide both sides by 60%x = (6 * 70%) / 60%x = 7and since he has made 6 shots already, he would need just one more to get 7 shots or 70%. if the explanation is too confusing, comment and i will try to