1. One student was upset with her grade on Test 2 and thought the test was too difficult. In her anger, she said, "There is no way the class average on this test was higher than a C." Can you conclude at a 0.05 level of significance that the average score on Test 2 was no higher than a 79?

Hypothesis rejected

Step-by-step explanation:

Lets use the t-test since the variance of the population is now known. We need to test the hypothesis that H_0: \mu \leq 79 \text{ vs } H_1: \mu > 79 . This is performed in R as follows:

t.test(tt$Test.2.Score,mu=79,alternative="greater")

One Sample t-test

data: tt$Test.2.Score

t = 2.9238, df = 69, p-value = 0.002337

alternative hypothesis: true mean is greater than 79

95 percent confidence interval:

81.26555 Inf

sample estimates:

mean of x

84.27143

Thus, we reject the null hypothesis and conclude that \mu > 79.

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue

the answer is; biodiversity resulting from few ancestors

adaptive radiation occurs when a population is subjected to a large natural environment with spatial ecological variations. the parts of the population in the different ecologies begin to adapt to their local environments. due to non-random mating across the large populations, this causes the different populations from the large population to speciate within their local environments. they, therefore, diverge to different species sharing a common ancestor.