In the last Election Candidate B received twice as many votes as candidate A. Candidate C received 25,000 fewer votes than candidate A. If a total of 164,000 votes were cast, how many votes did each candidate receive?

Therefore Candidate A , Candidate B and Candidate C received 47,250 votes, 94,500 votes and 22,250 votes respectively.

Step-by-step explanation:

Assume that, A received x votes.

In a election candidate B received twice as many votes as candidate A.

So, B received = 2x votes

Candidate C received 25,000 fewer votes than candidate A.

So, C received= x-25,000 votes.

According to the problem,

x+2x+x-25,000= 164,000

⇒ 4x= 164,000+25,000

⇒4x=189,000

A received = 47,250 votes

B received = 2x votes

                  =(2×47,250)

                  =94,500

C received=x-25,000

                 =(47,250-25,000)

                =22,250

Therefore Candidate A , Candidate B and Candidate C received 47,250 votes, 94,500 votes and 22,250 votes respectively.

1.5%

step-by-step explanation:

answer: the common difference is -0.10