I need help with this exponential function problem, please show work :)

a = 12. b =1/6. g(x) = 12(1/6)^x

Step-by-step explanation:

g(x) =a * b^x.

First we should use the give values to us in the table which are x=0 then g(x) = 12 and if x =1, then g(x) = 2. We should plug in the value where x = 0 since any value to the power of 0 is 1. 12= a *b^0. 12=a *1. Then we will get the value of a which is 12. Then we plug in our second given value to find b. 2 = 12 * b^1. First we will divide both sides by 12 to find b. 2/12 = 1/6. since any value to the power of 1 is itself then b =1/6. Then you will have a = 12. b =1/6 so g(x) = 12(1/6)^x

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2