Joseph made a model rocket by attaching a cone
on top of a cylinder, as shown in the diagram.
The cone has a height of 12 inches and slant
height of 13 inches. The cylinder has a height
of 18 inches and radius of 5 inches.
a) What is the surface area of the model rocket
(without the base)?

b) What is the volume of the model rocket?

Area = 270π inches squared. Volume = 550π inches cubed

Step-by-step explanation:

Surface Area:

Cylinder Area=2πrh+2πr^2= 180π+50π=230π inches squared.

Cone Area = πr(r+√(h^2+r^2)) = 5π(18) = 90π inches squared.

Total Area = 230π+90π = 320π inches squared.

Total Area - base = 320π-50π = 270π inches squared.

Volume:

Cylinder volume = πr^2h = 450π inches cubed

Cone volume = πr^2(h/3) = 100π inches cubed

Total Volume = 550π inches cubed

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

step-by-step explanation:

answers available in this download

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