3.25 in dimes and nickels, were distributed among 45 boys. If each boy received one coin, how many received dimes?

20

Step-by-step explanation:

Given that: $3.25 in dimes and nickels were distributed among 45 boys.

1 nickel = $0.05

1 dime = $0.10

Let number of coins of dimes be x and the number of coins of nickel be 45-x.

Hence,

0.10x + 0.05(45-x)=3.25

0.10x+2.25-0.05x=3.25

0.05x=3.25-2.25

0.05x=1

x= 1/0.05

x=20

45-x

45-20=25

i think it is c, not positive though

step-by-step explanation: