The graph represents the function f(x) = 10(2)x.

On a coordinate plane, an exponential growth function approaches y = 0 in the second quadrant and goes through points (negative 1, 5), (0, 10), (1, 20), (2, 40).
How would the graph change if the b value in the equation is decreased but remains greater than 1? Check all that apply.

Step-by-step explanation:

Here you have an exponential function.  The proper format is

f(x) = 10(2)^x, where the " ^ " represents exponentiation.  

If (-1, 5) is a point on this graph, then 5 = 10(2)^1 must be true.  Then

5 = 10(2)^(-1)   =>  5 = 10/2 = 5.  This is true.

You mention a "b value" but do not show it in the equation.  Please repost this question and show b.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

the answer is c

hope this !