Proximate the real zeros of f(x)=x^2+5x+3 to the nearest tenth The zeros are about and about

x = sqrt(13)/2 - 5/2 or x = -5/2 - sqrt(13)/2

or decimal -0.69722436226800535344038936626475202687435171307737689364

Step-by-step explanation:

Solve for x:

x^2 + 5 x + 3 = 0

Subtract 3 from both sides:

x^2 + 5 x = -3

Add 25/4 to both sides:

x^2 + 5 x + 25/4 = 13/4

Write the left hand side as a square:

(x + 5/2)^2 = 13/4

Take the square root of both sides:

x + 5/2 = sqrt(13)/2 or x + 5/2 = -sqrt(13)/2

Subtract 5/2 from both sides:

x = sqrt(13)/2 - 5/2 or x + 5/2 = -sqrt(13)/2

Subtract 5/2 from both sides:

 x = sqrt(13)/2 - 5/2 or x = -5/2 - sqrt(13)/2

answer: are you

step-by-step explanation:

exa:

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3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.