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Mathematics, 05.05.2020 23:58 tpenubothu24

One focus of a hyperbola is located at (−6, 2). One vertex of the hyperbola is located at (−4, 2). The center is (−1, 2).

What is the equation of the hyperbola?

(x+1)^2/16 - (y-2)^2/9 = 1

(x+1)^2/9 - (y-2)^2/16 = 1

(x-2)^2/16 - (y+1)^2/9 = 1

(x-2)^2/9 - (y+1)^2/16 = 1

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