Tickets for a dance recital cost $15 for adults and $7 for children. The dance company sold 253 tickets, and the total receipts were $2,771. How many adult tickets and how many child tickets were sold?

Adult tickets =125

Child tickets = 128

Step-by-step explanation:

Let the number of adult and children tickets sold be x and y respectively

So that

x+y= 2531

Since total sales/receipt is $2,771

And given that tickets for a dance recital cost $15 for adults and $7 for children hence

15x+7y= 27712

Solving equation 1 and 2 simultaneously we have

x+y= 2531

15x+7y= 27712

Let us multiply equation 1 by 15 to get equation 3 to eliminate x and subtract equation 2 from 3

15x+15y=37953

-{15x+7y= 27712

0+8y=1024

8y= 1024

y= 1024/8

y= 128 tickets

So solve for x let us put y= 128 in equation 1

x+ 128=253

x=253-128

x= 125 tickets

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation:

linear pair postulates