claim: the mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. for a random sample of 140 adult males, the mean pulse rate is 70.4 bpm and the standard deviation is 11.1 bpm. find the value of the test statistic.

93.19%

Step-by-step explanation:

We have that the mean (m) is equal to 70.4, the standard deviation (sd) 11.1 and the sample size (n) = 140

They ask us for P (x =69)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (69 - 70.4) / (11.1 / (140 ^ (1/2)))

z = 1.49

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <1.49) = 0.9319

The probability is 93.19%

898.1666667

step-by-step explanation:

5389/6 = 898.1666667

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: